-120x^2+14x+49=0

Solution for -120x^2+14x+49=0 equation:

-120x^2+14x+49=0

a = -120; b = 14; c = +49;
Δ = b2-4ac
Δ = 142-4·(-120)·49
Δ = 23716
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{23716}=154$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-154}{2*-120}=\frac{-168}{-240}
=7/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+154}{2*-120}=\frac{140}{-240}
=-7/12
$